e^-5j how to calculate??

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e^-5(pi)j

does j = i =sqrt(-1)  ?

$e^{-5\pi i}=cos(-5\pi)+isin(-5\pi)\\ e^{-5\pi i}=cos(\pi)+isin(\pi)\\ e^{-5\pi i}=-1+i*0\\ e^{-5\pi i}=-1$

$e^{-5j\pi}=-1$

Euler's identity: $e^{j\pi} = -1$

$\begin{array}{rcl} e^{j\pi} &=& -1 \qquad &|\qquad ()^{-5}\\ (e^{j\pi})^{-5} &=& (-1)^{-5}\\ e^{-5j\pi}&=& \frac {1}{(-1)^5} = \end{array}$

$=\frac{1}{-1} = -1$