+0  
 
+1
378
1
avatar

e^(i*2*pi) * (-1)^98 * (343)^(1/3)

 Jun 8, 2017

Best Answer 

 #1
avatar+2298 
+1

I will assume for this problem that i is for the imaginary number. If I should assume otherwise, tell me. I will, of course, simplify the given expression:
 

 

 

\(e^{i*2*\pi}*(-1)^{98}*343^{\frac{1}{3}}\) We will use an imaginary number rule here stating that \(e^{ia\pi}=(-1)^a, \text{so}\hspace{1mm}e^{i2\pi}=(-1)^2=1\). Of course, something multiplied by 1 is itself, so we are left with the other part.
\((-1)^{98}*343^{\frac{1}{3}}\) -1 raised to an even power is always one, so this is another part of the multiplication that we can eliminate.
\(343^{\frac{1}{3}}\) \(a^{\frac{1}{3}}=\sqrt[3]{a}\),so let's apply this rule, too.
\(\sqrt[3]{343}=7\) 7 is your answer.
   
   
   
   
   
   
 Jun 9, 2017
 #1
avatar+2298 
+1
Best Answer

I will assume for this problem that i is for the imaginary number. If I should assume otherwise, tell me. I will, of course, simplify the given expression:
 

 

 

\(e^{i*2*\pi}*(-1)^{98}*343^{\frac{1}{3}}\) We will use an imaginary number rule here stating that \(e^{ia\pi}=(-1)^a, \text{so}\hspace{1mm}e^{i2\pi}=(-1)^2=1\). Of course, something multiplied by 1 is itself, so we are left with the other part.
\((-1)^{98}*343^{\frac{1}{3}}\) -1 raised to an even power is always one, so this is another part of the multiplication that we can eliminate.
\(343^{\frac{1}{3}}\) \(a^{\frac{1}{3}}=\sqrt[3]{a}\),so let's apply this rule, too.
\(\sqrt[3]{343}=7\) 7 is your answer.
   
   
   
   
   
   
TheXSquaredFactor Jun 9, 2017

19 Online Users

avatar
avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.