+2440 I will assume for this problem that i is for the imaginary number. If I should assume otherwise, tell me. I will, of course, simplify the given expression:
| \(e^{i*2*\pi}*(-1)^{98}*343^{\frac{1}{3}}\) | We will use an imaginary number rule here stating that \(e^{ia\pi}=(-1)^a, \text{so}\hspace{1mm}e^{i2\pi}=(-1)^2=1\). Of course, something multiplied by 1 is itself, so we are left with the other part. |
| \((-1)^{98}*343^{\frac{1}{3}}\) | -1 raised to an even power is always one, so this is another part of the multiplication that we can eliminate. |
| \(343^{\frac{1}{3}}\) | \(a^{\frac{1}{3}}=\sqrt[3]{a}\),so let's apply this rule, too. |
| \(\sqrt[3]{343}=7\) | 7 is your answer. |
+2440 I will assume for this problem that i is for the imaginary number. If I should assume otherwise, tell me. I will, of course, simplify the given expression:
| \(e^{i*2*\pi}*(-1)^{98}*343^{\frac{1}{3}}\) | We will use an imaginary number rule here stating that \(e^{ia\pi}=(-1)^a, \text{so}\hspace{1mm}e^{i2\pi}=(-1)^2=1\). Of course, something multiplied by 1 is itself, so we are left with the other part. |
| \((-1)^{98}*343^{\frac{1}{3}}\) | -1 raised to an even power is always one, so this is another part of the multiplication that we can eliminate. |
| \(343^{\frac{1}{3}}\) | \(a^{\frac{1}{3}}=\sqrt[3]{a}\),so let's apply this rule, too. |
| \(\sqrt[3]{343}=7\) | 7 is your answer. |
