#1**+1 **

I will assume for this problem that i is for the imaginary number. If I should assume otherwise, tell me. I will, of course, simplify the given expression:

\(e^{i*2*\pi}*(-1)^{98}*343^{\frac{1}{3}}\) | We will use an imaginary number rule here stating that \(e^{ia\pi}=(-1)^a, \text{so}\hspace{1mm}e^{i2\pi}=(-1)^2=1\). Of course, something multiplied by 1 is itself, so we are left with the other part. |

\((-1)^{98}*343^{\frac{1}{3}}\) | -1 raised to an even power is always one, so this is another part of the multiplication that we can eliminate. |

\(343^{\frac{1}{3}}\) | \(a^{\frac{1}{3}}=\sqrt[3]{a}\),so let's apply this rule, too. |

\(\sqrt[3]{343}=7\) | 7 is your answer. |

TheXSquaredFactor
Jun 9, 2017

#1**+1 **

Best Answer

I will assume for this problem that i is for the imaginary number. If I should assume otherwise, tell me. I will, of course, simplify the given expression:

\(e^{i*2*\pi}*(-1)^{98}*343^{\frac{1}{3}}\) | We will use an imaginary number rule here stating that \(e^{ia\pi}=(-1)^a, \text{so}\hspace{1mm}e^{i2\pi}=(-1)^2=1\). Of course, something multiplied by 1 is itself, so we are left with the other part. |

\((-1)^{98}*343^{\frac{1}{3}}\) | -1 raised to an even power is always one, so this is another part of the multiplication that we can eliminate. |

\(343^{\frac{1}{3}}\) | \(a^{\frac{1}{3}}=\sqrt[3]{a}\),so let's apply this rule, too. |

\(\sqrt[3]{343}=7\) | 7 is your answer. |

TheXSquaredFactor
Jun 9, 2017