We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
35
2
avatar

The Richter scale is used to measure the intensity of an earthquake. If E, measured in joules, is the energy released during an earthquake, then the magnitude is given by,

 

M = 2/3 log(E/E_0) 

 

Where E_0 = 10^4.4 joules

 

i. If 8 x 10^14 joules of energy are released during an earthquake, what is the magnitude of the earthquake?

 

 

 

ii. How much energy will be released in an earthquake with a magnitude of 5.9?

 Mar 11, 2019
 #1
avatar
+1

i. Since the amount of energy, E in this instance, is 8* 10^14, just plug 8*10^14 into (E/E_0). Then 8*10^14 / 10^4.4 would get you the right side of the equation. After that, calculating the magnitude would mean 2/3 log 31848573644.3(according to google calculator, but don't trust me on this one, I'd recommend you find some way to calculate it). solving 2/3 log 31848573644.3 you get 7.00205999133(I'd really recommend a calculator for this one).

 

 

ii. lol I can't solve it rn, since I'm on a car, but I'd imagine that you would do the reverse of #1, as you know that M is 5.9, and you already have E_0, so you can write the equation 2/3 log (E * 10^4.4) = 5.9, and from then on, you'd need some knowledge of logs and probably a calculator with u to solve it

 Mar 11, 2019
 #2
avatar
+1

1 - M = 2/3 log_10((8×10^14)/(1×10^4.4)) =~7 - Magnitude on the Richter scale.

 

2 - solve 5.9 = 2/3 log_10(P/(1×10^4.4)) for P

P = 1.77828×10^13 - Joules - the amount of energy released in a 5.9 Magnitude earthquake.

 Mar 11, 2019

9 Online Users