What is f'(x) when f(x) = 10-10e**(-2x)?
d/dx (e^(-2x) ) = -2e^(-2x) from the Chain Rule.
So f'(x) = -20 e^(-2x)
You've forgotten one of the minus signs Guest #1
f'(x) = 0 - 10*(-2)e-2x or f'(x) = 20e-2x
.
