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0
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avatar+1832 

I want explanation for question number 5 . . 

 

physics
xvxvxv  Feb 19, 2015

Best Answer 

 #6
avatar+26619 
+15

Original force on charge 1 from the others f = K(q1*q2/d2 + q1*q3/(āˆš2*d)2 + q1*q4/d2) where K is a constant (I've assumed d1 and d3 are on opposite corners).

(Strictly, we should add these as vectors, but that's an unnecessary complication here.)

 

If all the q terms are multiplied by 2 and everything else remains the same it is easy to see that a factor of 4 increases each term, and hence the force on charge 1 quadruples.  The same argument applies to all the other charges, so SevenUp is correct.

.

Alan  Feb 23, 2015
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8+0 Answers

 #1
avatar+92164 
+5

Does anyone want to answer one of 315's physics questions?

Melody  Feb 20, 2015
 #2
avatar+1832 
0

Any one ? 

xvxvxv  Feb 21, 2015
 #3
avatar+394 
+15

I believe the answer is C, they quadruple. Iā€™m not absolutely certain, but it is logical because each charge increases 100% and there are 4 charges. I know that the potential at any point on the square is the algebraic sums of the individual charges. So a change of magnitude of a charge is directly proportional.

 

Alan can verify the accuracy or error of my statements.

 

Your question was lost in the sea, even after Melody bumped it.

 

_7UP_

SevenUP  Feb 21, 2015
 #4
avatar+1832 
+5

Thank you Seven up .. amd waiting for Alan .. ~ 

xvxvxv  Feb 21, 2015
 #5
avatar+92164 
+5

Alan, could you please take a look at this question.  

 

I think 315 and SevenUp are both keen to see your answer.   

Melody  Feb 22, 2015
 #6
avatar+26619 
+15
Best Answer

Original force on charge 1 from the others f = K(q1*q2/d2 + q1*q3/(āˆš2*d)2 + q1*q4/d2) where K is a constant (I've assumed d1 and d3 are on opposite corners).

(Strictly, we should add these as vectors, but that's an unnecessary complication here.)

 

If all the q terms are multiplied by 2 and everything else remains the same it is easy to see that a factor of 4 increases each term, and hence the force on charge 1 quadruples.  The same argument applies to all the other charges, so SevenUp is correct.

.

Alan  Feb 23, 2015
 #7
avatar+92164 
+5

Thanks Alan  

Melody  Feb 23, 2015
 #8
avatar+1832 
+5

Thank you Alan to make it clear .. 

thank you Melody and seven up 

xvxvxv  Feb 25, 2015

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