Solve the following system:
{-4/3 - x/3 = -2 | (equation 1)
x/3 - (2 y)/3 = 4 | (equation 2)
Express the system in standard form:
{-x/3+0 y = -2/3 | (equation 1)
x/3 - (2 y)/3 = 4 | (equation 2)
Add equation 1 to equation 2:
{-x/3+0 y = -2/3 | (equation 1)
0 x - (2 y)/3 = 10/3 | (equation 2)
Multiply equation 1 by -3:
{x+0 y = 2 | (equation 1)
0 x - (2 y)/3 = 10/3 | (equation 2)
Multiply equation 2 by 3/2:
{x+0 y = 2 | (equation 1)
0 x - y = 5 | (equation 2)
Multiply equation 2 by -1:
{x+0 y = 2 | (equation 1)
0 x+y = -5 | (equation 2)
Collect results:
Answer: |x = 2 and y = -5
