Enter all positive solutions to $4x^{1/3}-2\frac{x}{x^{2/3}}=7+\sqrt[3]{x}$.
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Simplifying this we have :
4x^(1/3) - 2x^(1/3) = 7 + x^(1/3)
3x^(1/3) - 2x^(1/3) = 7
x^(1/3) = 7 cube both sides
x = 7^3 = 343