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Solve for $x$: $4x^{1/3}-2 \cdot \frac{x}{x^{2/3}}=7+\sqrt[3]{x}$.

 Jun 24, 2021

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 #1
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let y = \(\sqrt[3]{x}\):

\(4y-\frac{2y^3}{y^2}=7+y\\4y-2y=7+y\\y=7\)

\(7=\sqrt[3]{x}\\x=343\)

 Jun 24, 2021
 #1
avatar+449 
+1
Best Answer

let y = \(\sqrt[3]{x}\):

\(4y-\frac{2y^3}{y^2}=7+y\\4y-2y=7+y\\y=7\)

\(7=\sqrt[3]{x}\\x=343\)

textot Jun 24, 2021

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