Solve for $x$: $4x^{1/3}-2 \cdot \frac{x}{x^{2/3}}=7+\sqrt[3]{x}$.
let y = \(\sqrt[3]{x}\):
\(4y-\frac{2y^3}{y^2}=7+y\\4y-2y=7+y\\y=7\)
\(7=\sqrt[3]{x}\\x=343\)
