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Find the roots of the following quadratic equation:

 

a) f1(x)=2x2−9x+4

 

b) f(x)=x2−9

 

c) f3(x)=(x+π)(x−99)

 

d) f(x)=1x2−3x+5

 Jan 14, 2017

Best Answer 

 #2
avatar+14986 
+5

Hi Chris, thank you for your attention.

a) is wrong.

 

a) f1(x)=2x2−9x+4

\(f_1(x)=2x^2-9x+4=0\)

               a         b        c

\(\large x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

 

\(\large x = {9 \pm \sqrt{81-4\times 2\times 4} \over 2\times 2}\)

 

\(\large x=\frac{9\pm7}{4}\)

 

\(\large x_1=4\)

 

\(\large x_2=\frac{1}{2}\)

 

laugh !

 Jan 14, 2017
 #1
avatar+14986 
+5

Find the roots of the following quadratic equation:

 

a) f1(x)=2x2−9x+4

\(f_1(x)=2x^2-9x=0\)

\(x_1=0\)

\(2x-9=0\)

\(x_{2;3}=\pm3\)

 

b) f(x)=x2−9

\(f(x)=x^2-9\)

\(x_{1;2}=\pm3\)

 

c) f3(x)=(x+π)(x−99)

\(f_3(x)=(x+\pi)(x-99)\)

\(x_1=-\pi\)

\(x_2=99\)

 

d) f(x)=1x2−3x+5

\(f(x)=1x^2-3x+5\)

               a          b         c

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

\(x = {3 \pm \sqrt{(-3)^2-4\times 1\times5} \over 2\times 1}\)

\(x=\frac{3\pm\sqrt{-11}}{2}\)

\(x_{1;2}=1.5\pm i\frac{\sqrt {11}}{2}\)

 

laugh   !

\(\)

 Jan 14, 2017
 #2
avatar+14986 
+5
Best Answer

Hi Chris, thank you for your attention.

a) is wrong.

 

a) f1(x)=2x2−9x+4

\(f_1(x)=2x^2-9x+4=0\)

               a         b        c

\(\large x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

 

\(\large x = {9 \pm \sqrt{81-4\times 2\times 4} \over 2\times 2}\)

 

\(\large x=\frac{9\pm7}{4}\)

 

\(\large x_1=4\)

 

\(\large x_2=\frac{1}{2}\)

 

laugh !

asinus  Jan 14, 2017

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