Find the roots of the following quadratic equation:
a) f1(x)=2x2−9x+4
b) f(x)=x2−9
c) f3(x)=(x+π)(x−99)
d) f(x)=1x2−3x+5
Hi Chris, thank you for your attention.
a) is wrong.
a) f1(x)=2x2−9x+4
\(f_1(x)=2x^2-9x+4=0\)
a b c
\(\large x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
\(\large x = {9 \pm \sqrt{81-4\times 2\times 4} \over 2\times 2}\)
\(\large x=\frac{9\pm7}{4}\)
\(\large x_1=4\)
\(\large x_2=\frac{1}{2}\)
!
Find the roots of the following quadratic equation:
a) f1(x)=2x2−9x+4
\(f_1(x)=2x^2-9x=0\)
\(x_1=0\)
\(2x-9=0\)
\(x_{2;3}=\pm3\)
b) f(x)=x2−9
\(f(x)=x^2-9\)
\(x_{1;2}=\pm3\)
c) f3(x)=(x+π)(x−99)
\(f_3(x)=(x+\pi)(x-99)\)
\(x_1=-\pi\)
\(x_2=99\)
d) f(x)=1x2−3x+5
\(f(x)=1x^2-3x+5\)
a b c
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
\(x = {3 \pm \sqrt{(-3)^2-4\times 1\times5} \over 2\times 1}\)
\(x=\frac{3\pm\sqrt{-11}}{2}\)
\(x_{1;2}=1.5\pm i\frac{\sqrt {11}}{2}\)
!
\(\)
Hi Chris, thank you for your attention.
a) is wrong.
a) f1(x)=2x2−9x+4
\(f_1(x)=2x^2-9x+4=0\)
a b c
\(\large x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
\(\large x = {9 \pm \sqrt{81-4\times 2\times 4} \over 2\times 2}\)
\(\large x=\frac{9\pm7}{4}\)
\(\large x_1=4\)
\(\large x_2=\frac{1}{2}\)
!