A creature on the moon throws a rock off a cliff. The height of the rock above the surface of the moon, in meters, t seconds after it is thrown is given by h(t) = −t^2+ 8t + 10. When does the rock hit the surface of the moon?
pls help as this is urgent
+1223 The rock hits the surface when the height is 0, or when \(-t^2 + 8t + 10 = 0\)
\(t^2 - 8t - 10 = 0 \)
Use the quadratic formula: t = -1.099 and 9.099. Time can't be negative, so the answer is t = 9.099.
+1223 The rock hits the surface when the height is 0, or when \(-t^2 + 8t + 10 = 0\)
\(t^2 - 8t - 10 = 0 \)
Use the quadratic formula: t = -1.099 and 9.099. Time can't be negative, so the answer is t = 9.099.
