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A creature on the moon throws a rock off a cliff. The height of the rock above the surface of the moon, in meters, t seconds after it is thrown is given by h(t) = −t^2+ 8t + 10. When does the rock hit the surface of the moon?

 

pls help as this is urgent

 Feb 20, 2021

Best Answer 

 #1
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+1

The rock hits the surface when the height is 0, or when \(-t^2 + 8t + 10 = 0\)

 

\(t^2 - 8t - 10 = 0 \)

 

Use the quadratic formula: t = -1.099 and 9.099. Time can't be negative, so the answer is t = 9.099.

 Feb 20, 2021
 #1
avatar+944 
+1
Best Answer

The rock hits the surface when the height is 0, or when \(-t^2 + 8t + 10 = 0\)

 

\(t^2 - 8t - 10 = 0 \)

 

Use the quadratic formula: t = -1.099 and 9.099. Time can't be negative, so the answer is t = 9.099.

CubeyThePenguin Feb 20, 2021
 #2
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What is the formula?

Guest Feb 22, 2021

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