find standard form of equation and graph of circle where:

center at (3,-2) and tangent to y = 2

Guest Jan 21, 2018

#1**+1 **

The standard equation form for a circle is

(x-h)^2 + (y-k)^2 = r^2

where h,k is the center....

so we have

(x-3)^2 + (y+2)^2 = r^2 the radius has to be big enough to have tangent of y = 2 (which is 4 units from the center)

so r = 4

(x-3)^2 + (y+2)^2 = 4^2

Here is a graph:

ElectricPavlov
Jan 21, 2018