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find standard form of equation and graph of circle where:

center at (3,-2) and tangent to y = 2

 Jan 21, 2018
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The standard equation form for a circle is

(x-h)^2 + (y-k)^2 = r^2

 

where h,k is the center....

so we have

(x-3)^2 + (y+2)^2 = r^2        the radius has to be big enough to have tangent of y = 2  (which is 4 units from the center)

so r = 4

 

(x-3)^2 + (y+2)^2 = 4^2

Here is a graph:

 Jan 21, 2018

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