The equation of the circle shown in the following diagram can be written as x^2 + Ay^2 + Bx + Cy + D = 0. Find A + B + C + D.
The radius is the distance between the two points = sqrt 61
given (h,k) the center as (-1,1)...the standard form circle equation becomes
(x+1)2 + ( y-1)2 = ( sqrt 61)2 expand
x2 + 2x +1 + y2 -2y +1 - 61 = 0 <======= simplify to find A B C D to finish