The equation of the circle shown in the following diagram can be written as x^2 + Ay^2 + Bx + Cy + D = 0. Find A + B + C + D.

Guest Feb 9, 2022

#1**+1 **

The radius is the distance between the two points = sqrt 61

given (h,k) the center as (-1,1)...the standard form circle equation becomes

(x+1)^{2} + ( y-1)^{2} = ( sqrt 61)2 expand

x^{2} + 2x +1 + y^{2} -2y +1 - 61 = 0 <======= simplify to find A B C D to finish

ElectricPavlov Feb 9, 2022