+1234 Find the coordinates of the center of the circle.
The points on the circle are (22,15), (-25,0), (22,-29).
+44 Are you familiar with the distance formula? \(\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\)
You can plug in \(x_2\) as 22 and \(x_1\) as \(x\), and the corresponding values for y (15 or -29 and y) and make three equations
(for context, (x, y) is the center of the circle). Then, you solve the system!
If you have any questions, please contact!
-webcalcman
+129845 Using the square of the distance formula, equate r^2
(x -22)^2 + (y -15)^2 = (x -22)^2 + ( y + 29)^2
(y -15)^2 = (y +29)^2
y^2 -30y + 225 = y^2 + 58y + 841
-88y = 616
y = -616/88 = -7
So....using this again
(x -22)^2 + (-7-15)^2 = (x + 25)^2 + (-7)^2
x^2 - 44x + 484 + 484 = x^2 + 50x + 625 + 49
-44x + 968 = 50x + 674
-94x = -294
x = 294/94 = 147/47
The center is ( 147 / 47 , -7)
