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Write an equation of the line that passes through (-3,3) and is perpendicular to the line 2y=8x-6

 Mar 8, 2021
 #1
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Here you go :-

 

2y = 8x - 6 

⇒y = 4x - 3

\({dy \over dx} = 4\)

Slope of perpendicular line = -1/4

Hence, equation of line

\(y - 3 = ({-1\over 4})({x - (-3)})\)

\(4y - 12 = -x - 3\)

\(x + 4y = 9 \)

 Mar 9, 2021

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