Write an equation of the line that passes through (-3,3) and is perpendicular to the line 2y=8x-6
+526 Here you go :-
2y = 8x - 6
⇒y = 4x - 3
⇒\({dy \over dx} = 4\)
Slope of perpendicular line = -1/4
Hence, equation of line
\(y - 3 = ({-1\over 4})({x - (-3)})\)
\(4y - 12 = -x - 3\)
⇒\(x + 4y = 9 \)
