A line segment has endpoints at (8, 3) and (2,5). What would be the equation of this line's perpendicular bisector?
+1253 Midpoint: (5, 4)
Slope: -1/3
Bisector: y = 3x+b
Substitute x=5, y=4
4 = 15+b
b = -11
Answer: y = 3x-11
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