Write the equation for a line that has a slope of -2 and passes though the point (4,7)

Guest Aug 1, 2017

#1**+1 **

In order to do this problem, you must understand not slope-intercept form but point-slope form.

Point-slope form is the following equation:

\(y-k=m(x-h)\)

m = slope of the line

(h,k) is a point (any point will do) on the line.

We already have all of this information given to us already, so this problem is relatively easy. m = -2 and (h,k) is (4,7). Let's plug this in:

\(y-k=m(x-h)\) | Plug in m as -2, h as 4, and k as 7. |

\(y-7=-2(x-4)\) | You could say that you are done because you have written an equation for the conditions, but let's transform this into slope-intercept form by distributing the -2. |

\(y-7=-2x+8\) | Add 7 to both sides. |

\(y=-2x+15\) | |

TheXSquaredFactor
Aug 1, 2017

#1**+1 **

Best Answer

In order to do this problem, you must understand not slope-intercept form but point-slope form.

Point-slope form is the following equation:

\(y-k=m(x-h)\)

m = slope of the line

(h,k) is a point (any point will do) on the line.

We already have all of this information given to us already, so this problem is relatively easy. m = -2 and (h,k) is (4,7). Let's plug this in:

\(y-k=m(x-h)\) | Plug in m as -2, h as 4, and k as 7. |

\(y-7=-2(x-4)\) | You could say that you are done because you have written an equation for the conditions, but let's transform this into slope-intercept form by distributing the -2. |

\(y-7=-2x+8\) | Add 7 to both sides. |

\(y=-2x+15\) | |

TheXSquaredFactor
Aug 1, 2017