Find all values of x such that \sqrt{4x^2} + \sqrt{x^2} = 6 + 3x.
Simplifying, we have
\(2x + x = 6 + 3x\)
\(3x = 6 + 3x\)
\(0 = 6\)
Since 0 can't equal to 6, this equation has no solutions.
