Find all values of x such that \sqrt{4x^2} + \sqrt{x^2} = 6 + 3x.

Simplifying, we have

\(2x + x = 6 + 3x\)

\(3x = 6 + 3x\)

\(0 = 6\)

Since 0 can't equal to 6, this equation has no solutions.