How do i solve this equation: (x^2 - 2) (2x+7) = 0. Do i take the Square root of (x^2 - 2) (2x+7). Then what?
Solve for x:
(2 x + 7) (x^2 - 2) = 0
Split into two equations:
2 x + 7 = 0 or x^2 - 2 = 0
Subtract 7 from both sides:
2 x = -7 or x^2 - 2 = 0
Divide both sides by 2:
x = -7/2 or x^2 - 2 = 0
Add 2 to both sides:
x = -7/2 or x^2 = 2
Take the square root of both sides:
Answer: |x = -7/2 or x = sqrt(2) or x = -sqrt(2)
