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Let f(x)=x^2 -2x. Find all real numbers x such that f(x)=3.

 Aug 17, 2021
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Okay, they tell us that f(x) is 3, so lets just bring that into f(x)=x^2 -2x

3=x^2 -2x

We can solve by guess and check, but we can also use the quadratic formula.

Let's move 3 to the other side.

x^2 -2x -3=0

We get 3 and (-1), using the quadratic formula. If you don't know what that is, you can find how to use it on google. I hope you find this useful.

 Aug 17, 2021

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