Enter all positive solutions to $4x^{1/3}-2\frac{x}{x^{2/3}}=7+\sqrt[3]{x}/2$.
\( $4x^{1/3}-2\frac{x}{x^{2/3}}=7+\sqrt[3]{x}/2$\)
4x^(1/3) - 2x^(1/3) = 7 + x^(1/3) / 2
2x^(1/3) = 7 + x^(1/3) / 2 multiply through by 2
4x^(1/3) = 14 + x^(1/3)
3x^(1/3) = 14
x^(1/3) = 14 / 3 cube both sides
x = (14/ 3)^3 = 2744 / 27
