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# Equation

0
88
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Find the value of n that satisfies $2(n+1)!+6n!=10$, where $n! = n\cdot (n-1)\cdot (n-2) \cdots 2\cdot 1$.

Jun 11, 2022

#1
+2448
0

Just plug in n = 1, n = 2, and n = 3.

You should find it pretty quickly.

Jun 11, 2022