\((3x+2)(x+4)=\frac{4x^2+8x+8x^2}{2x}\)
simplify
\(3x^2+24x+48=2x+4+4x\)
simplify
\(3x^2+24x+48=6x+4\)
subtract 6x+4
\(3x^2+18x+44=0\)
quadratic formula
\(\frac{-18 \pm \sqrt{18^2-4(3)(44)}}{2(3)}\)
After simplifying the quadratic formula, we get
\(-3\pm\frac{i\sqrt{194}}{6}\)
so that's our answer :)