Solve for x:
0 = -(16 x^2)+40 x+2
0 = -16 x^2+40 x+2 is equivalent to -16 x^2+40 x+2 = 0:
-16 x^2+40 x+2 = 0
Divide both sides by -16:
x^2-(5 x)/2-1/8 = 0
Add 1/8 to both sides:
x^2-(5 x)/2 = 1/8
Add 25/16 to both sides:
x^2-(5 x)/2+25/16 = 27/16
Write the left hand side as a square:
(x-5/4)^2 = 27/16
Take the square root of both sides:
x-5/4 = (3 sqrt(3))/4 or x-5/4 = -(3 sqrt(3))/4
Add 5/4 to both sides:
x = 5/4+(3 sqrt(3))/4 or x-5/4 = -(3 sqrt(3))/4
Add 5/4 to both sides:
Answer: | x = 5/4+(3 sqrt(3))/4 or x = 5/4-(3 sqrt(3))/4
you Can Use quadratic formula by plugging those Numbers in Use - infront of surd fór one Ánd + fór other
