+118608 Hello birthdaygirl, welcome to the forum. :)
I am curious, is it your birthday everyday ??
x^2+y^2-8x-6y+24=0
\(\mbox{We have to rearrange it into this form}\\ (x-h)^2+(y-k)^2=r^2 \qquad \\centre\;(h,k) \qquad radius=r\\~\\ x^2+y^2-8x-6y+24=0\\ x^2-8x\qquad+y^2-6y=-24\\ x^2-8x+(\frac{8}{2})^2\qquad+y^2-6y+(\frac{6}{2})^2=-24+(\frac{8}{2})^2+(\frac{6}{2})^2\\ x^2-8x+16\qquad+y^2-6y+9=-24+16+9\\ (x-4)^2\qquad+(y-3)^2=1\\ \mbox{Circle centre (4,3) radius=1} \)
