What is the equation of a line that passes through the point (-7,2) and is perpendicular to the line whose equation is y = −2/5*x + 8?

Guest Apr 17, 2021

#1**0 **

The slope of our line y = x/4 + 5 is m = 1/4

Since we're coming up with the equation of a line that is perpendicular, the slope of our perpendicular line is the opposite reciprocal of 1/4, or m = - 4/1 or m = 4

Now, we need to find out the y-intercept of our perpendicular line. To do that we plug in (2, 7) into x and y as well as - 4 into m in the following equation:

y = mx + b

7 = (- 4)(2) + b

7 = - 8 + b

15 = b

Thus, with m = - 4 and b = 15, the equation of our perpendicular line is:

y = - 4x + 15

WARNING: Possibly wrong~ __Hannah__

Guest Apr 17, 2021

#2**+1 **

Slope of given line is m = -2/5 perpindicular is - 1/m = 5/2

Point slope form of the new line through -7, 2 is y-2 = 5/2 ( x - -7)

y = 5/2 x + 35/2 +2

y = 5/2 x + 39/2

Here is a graph ( which I used as a check):

https://www.desmos.com/calculator/kvm5df9b2n

ElectricPavlov Apr 17, 2021