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5x+3y=-6
10x+9=-12
Solve for x and y
 Feb 5, 2014
 #1
avatar+6251 
0
Quote:

5x+3y=-6
10x+9=-12
Solve for x and y



There are 2 main ways of doing this

1) solving for one variable in terms of the other

5x+3y=-6

y = 1/3(-6-5x)

Now plug this into the 2nd equation

10x + 9y = -12 (this isn't what you wrote but I assume it's what you meant)

10x + 9(1/3(-6-5x)) = -12

10x - 3(6+5x) = -12

-5x - 18 = -12

-5x = 6

x=-6/5

plugging this into the equation for y

y = 1/3(-6-5(-6/5))

y = 1/3(-6 + 6) = 0

2) the elimination method, you add or subtract multiples of one equation from the other.

5x + 3y = -6
10x + 9y = -12

subtract twice the first equation from the second equation

(10-2*5)x + (9-2*3)y = -12 - (2*-6)

3y = 0

y = 0;

plug this into the first equation

5x + 0 = -6

x = -6/5
 Feb 5, 2014
 #2
avatar+118654 
0
Hi Rom,
Do you know how to write a mixed numeral in LaTex so that the whole number is as big as the fraction part?
Thanks
140205 Elimination method LaTex.JPG
 Feb 5, 2014

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