what is (3x)^2-4y^2 if x=-2 and y=-3
= [3(-2)]2 - 4(-3)2
= 36 - 4(9) = 0
(3x)^2-4y^2 if x = -2 and y = -3
(3(-2))^2 - 4(-3)^2
(-6)^2 + 12^2
36 + 144
= 180
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