Loading [MathJax]/extensions/TeX/color.js
 
+0  
 
0
44
1
avatar+1556 

The vertices of triangle $ABC$ lie on the sides of equilateral triangle $DEF$, as shown.  If $CD = 5$, $CE = BD = 3$, and $\angle ACB = 90^\circ$, then find $AE$.

 Jan 15, 2024

2 Online Users

avatar