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Use benchmarks to estimate the value of each logarithm to the nearest tenth.

 

log_2(6.5)

 Jan 24, 2020
 #1
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I'm not sure what it means to "use benchmarks"; but:

21  =  2

22  =  4     --->     log24  =  2

23  =  8     --->     log28  =  3

              

So:  log26.5  is somewhere between  2  and  3; I would guess that it's about 2.5.

 Jan 24, 2020

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