Can be seen as two series:
1) (-1)^2 + (-1)^4 + (-1)^6.........+(-1)^2016=+1008 positive terms.
2) (-)^1 + (-1)^3 + (-1)^5...........+(-1)^2015=-1008 negative terms.
So, +1,008 -1,008 =0
2) Can also be summed up on Wolfram/Alpha as follows:
∑[ (-1)^(2n) +(-1)^(2n-1)] , n=1 to 2016, which gives this:
sum_(n=1)^2016((-1)^(2 n)+(-1)^(2 n-1)) = 0
