Evaluate a^2b^7/ a^3b as a fraction in index form when a = (2/5)^4 and b = (5/8)^3.
+118608 Evaluate a^2b^7/ a^3b as a fraction in index form when a = (2/5)^4 and b = (5/8)^3.
$$\\\frac{a^2b^7}{ a^3b}=\frac{b^6}{ a}=b^6\div a\\\\
\left(\frac{5^3}{8^3}\right)^6\div \frac{2^4}{5^4}=
\frac{5^{18}}{8^{18} }\times \frac{5^4}{2^4}=
\frac{5^{18}}{8^{18} }\times \frac{5^4}{2*8}=
\frac{5^{22}}{2*8^{19} }=
\frac{5^{22}}{2*(2^3)^{19} }=
\frac{5^{22}}{2*2^{57} }=
\frac{5^{22}}{2^{58} }$$
+118608 Evaluate a^2b^7/ a^3b as a fraction in index form when a = (2/5)^4 and b = (5/8)^3.
$$\\\frac{a^2b^7}{ a^3b}=\frac{b^6}{ a}=b^6\div a\\\\
\left(\frac{5^3}{8^3}\right)^6\div \frac{2^4}{5^4}=
\frac{5^{18}}{8^{18} }\times \frac{5^4}{2^4}=
\frac{5^{18}}{8^{18} }\times \frac{5^4}{2*8}=
\frac{5^{22}}{2*8^{19} }=
\frac{5^{22}}{2*(2^3)^{19} }=
\frac{5^{22}}{2*2^{57} }=
\frac{5^{22}}{2^{58} }$$
