2log(3)/9 + 3log(3)/9+ log(3)/9
2log(3)/9 + 3log(3)/9+ log(3)/9 =
(1/9) [ 2log(3) + 3log(3) + log(3) ] =
(1/9) [ 6 log(3) ] =
(6/9)log(3) =
(2/3)log(3)
Thanks for the help
No prob....