evaluate (exact form)

2log(3)/9 + 3log(3)/9+ log(3)/9  =

(1/9) [ 2log(3) + 3log(3) + log(3) ] =

(1/9) [ 6 log(3) ]  =

(6/9)log(3)  =

(2/3)log(3)

Thanks for the help

No prob....