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2log(3)/9 + 3log(3)/9+ log(3)/9

 Jan 9, 2016

Best Answer 

 #1
avatar+128079 
+10

2log(3)/9 + 3log(3)/9+ log(3)/9  =

 

(1/9) [ 2log(3) + 3log(3) + log(3) ] =

 

(1/9) [ 6 log(3) ]  =

 

(6/9)log(3)  =

 

(2/3)log(3)

 

 

 

cool cool cool

 Jan 9, 2016
 #1
avatar+128079 
+10
Best Answer

2log(3)/9 + 3log(3)/9+ log(3)/9  =

 

(1/9) [ 2log(3) + 3log(3) + log(3) ] =

 

(1/9) [ 6 log(3) ]  =

 

(6/9)log(3)  =

 

(2/3)log(3)

 

 

 

cool cool cool

CPhill Jan 9, 2016
 #2
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0

Thanks for the help

 Jan 9, 2016
 #3
avatar+128079 
0

No prob....

 

 

cool cool cool

 Jan 9, 2016

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