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Int (e^x) sqrt(1+e^x) dx

 Nov 28, 2016
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Take the integral:
 integral e^x sqrt(e^x + 1) dx
For the integrand e^x sqrt(e^x + 1), substitute u = e^x + 1 and du = e^x dx:
 = integral sqrt(u) du
The integral of sqrt(u) is (2 u^(3/2))/3:
 = (2 u^(3/2))/3 + constant
Substitute back for u = e^x + 1:
Answer: |= 2/3 (e^x + 1)^(3/2) + constant

 Nov 28, 2016

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