Evaluate -intergration between 1&16- x^-3/4dx

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Evaluate -intergration between 1&16- x^-3/4dx

Guest Aug 18, 2014

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Best Answer

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I assume we have

∫x^(-3/4) dx

So we have

4[16^(1/4) - 1^(1/4)] =

4[2 - 1] =

4 [1] = 4

CPhill Aug 18, 2014

1⁺⁰ Answers

+130511

+5

Best Answer

I assume we have

∫x^(-3/4) dx

So we have

4[16^(1/4) - 1^(1/4)] =

4[2 - 1] =

4 [1] = 4

CPhill Aug 18, 2014

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