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Evaluate $\frac{3+x(3+x)-3^2}{x-3+x^2}$ for $x=-2$

AWESOMEEE Jul 3, 2015

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Best Answer

+128578

+5

[ 3 + -2(3 + (-2)) - 3^2 ] / [ -2 -3 + (-2)^2 ] =

[3 -2(1) - 3^2] / [ -5 + 4] =

[ 1 - 9] / [-1] =

[-8] / (- 1) = 8/1 = 8

CPhill Jul 3, 2015

1⁺⁰ Answers

+128578

+5

Best Answer

[ 3 + -2(3 + (-2)) - 3^2 ] / [ -2 -3 + (-2)^2 ] =

[3 -2(1) - 3^2] / [ -5 + 4] =

[ 1 - 9] / [-1] =

[-8] / (- 1) = 8/1 = 8

CPhill Jul 3, 2015

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