Evaluate $\overline{i\left(\overline{\left(1+i\right)\left(\overline{13+2i}\right)}\right)}$.

Let's take this by parts

Conjugate of13 + 2i  =  13 - 2i

So  (1 + i) (13 - 2i)  =  13 + 13i - 2i - 2i^2  =   15 + 11i

And the connjugate of 15 + 11i   =  15 - 11i

So

i (15 - 11i) =  15i - 11i^2  =   11 + 15i

And the conjugate of this  is   11 - 15i