+0  
 
0
792
1
avatar

evaluate tan^2(4pi/3)- Sec^2(-11pi/6)

 Dec 17, 2014

Best Answer 

 #1
avatar+118723 
+5

$$\\ tan^2(4pi/3)- Sec^2(-11pi/6)\\\\
=tan^2(pi/3)- Sec^2(pi/6)\\\\
=(\sqrt3)^2-(\frac{2}{\sqrt3})^2\\\\
=3-\frac{4}{3}\\\\
=\frac{9-4}{3}\\\\
=\frac{5}{3}\\\\$$

.
 Dec 18, 2014
 #1
avatar+118723 
+5
Best Answer

$$\\ tan^2(4pi/3)- Sec^2(-11pi/6)\\\\
=tan^2(pi/3)- Sec^2(pi/6)\\\\
=(\sqrt3)^2-(\frac{2}{\sqrt3})^2\\\\
=3-\frac{4}{3}\\\\
=\frac{9-4}{3}\\\\
=\frac{5}{3}\\\\$$

Melody Dec 18, 2014

1 Online Users