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Evaluate the continued fraction [1,2,3,1,4,1,4,1,4...]

I'm not sure how to do this any help would be great.

 Feb 22, 2021
 #1
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c=0;i=0;p=0;d=reverse(1,2,3,1,4,1,4,1,4,1,4);c=1/(d[i] +c);printc;p=p+1;i++;if(i >Total =",p

 

1 / 4
4 / 5
5 / 24
24 / 29
29 / 140
140 / 169
169 / 816
816 / 985
985 / 3771
3771 / 8527
8527 / 12298
 

 Feb 22, 2021

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