+0  
 
+3
305
1
avatar

sin^2 0+sin^2 1+sin^2 2....sin^2 90

Guest Apr 20, 2015

Best Answer 

 #1
avatar+90970 
+8

$$\\sin^2 0+sin^2 1+sin^2 2....sin^2 90\\\\
=[sin^2 0+sin^2 1+...sin^244]\;\;\;+\;\;\;sin^245\;\;[+sin^246+....sin^2 90]\\\\
=(sin^2 0+sin^2 90)+....(sin^244+sin^246)+sin^245 \\\\
=(sin^2 0+cos^20)+....(sin^244+cos^244)\;\;+sin^245 \\\\
=(1)+....(1)\;\;+sin^245 \\\\
=45+sin^245\\\\
=45+(\frac{1}{\sqrt2})^2\\\\
=45\frac{1}{2}\\\\$$

Melody  Apr 20, 2015
Sort: 

1+0 Answers

 #1
avatar+90970 
+8
Best Answer

$$\\sin^2 0+sin^2 1+sin^2 2....sin^2 90\\\\
=[sin^2 0+sin^2 1+...sin^244]\;\;\;+\;\;\;sin^245\;\;[+sin^246+....sin^2 90]\\\\
=(sin^2 0+sin^2 90)+....(sin^244+sin^246)+sin^245 \\\\
=(sin^2 0+cos^20)+....(sin^244+cos^244)\;\;+sin^245 \\\\
=(1)+....(1)\;\;+sin^245 \\\\
=45+sin^245\\\\
=45+(\frac{1}{\sqrt2})^2\\\\
=45\frac{1}{2}\\\\$$

Melody  Apr 20, 2015

12 Online Users

avatar
avatar
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details