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sin^2 0+sin^2 1+sin^2 2....sin^2 90

 Apr 20, 2015

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sin20+sin21+sin22....sin290=[sin20+sin21+...sin244]+sin245[+sin246+....sin290]=(sin20+sin290)+....(sin244+sin246)+sin245=(sin20+cos20)+....(sin244+cos244)+sin245=(1)+....(1)+sin245=45+sin245=45+(12)2=4512

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 Apr 20, 2015
 #1
avatar+118703 
+8
Best Answer

sin20+sin21+sin22....sin290=[sin20+sin21+...sin244]+sin245[+sin246+....sin290]=(sin20+sin290)+....(sin244+sin246)+sin245=(sin20+cos20)+....(sin244+cos244)+sin245=(1)+....(1)+sin245=45+sin245=45+(12)2=4512

Melody Apr 20, 2015

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