#2**0 **

Hello! The answer "6" is wrong. This could be 6 if it was*e^((ln(3)+ln(2))*.

You can write*e^((ln(3)*ln(2))* as:

juicybebe101:its 6 you multiply the two powers

Hello! The answer "6" is wrong. This could be 6 if it was

You can write

3^(ln(2))

or

or

2^(ln(3))

So, the final result is:**2.1414860639032773**

Dms

So, the final result is:

Dms

Dms Mar 14, 2014

#3**0 **

yes if u plug it into a calculator thats what you will obtain however math_lover101 is asking for the exact exponent as previously stated

Dms:juicybebe101:its 6 you multiply the two powers

Hello! The answer "6" is wrong. This could be 6 if it wase^((ln(3)+ln(2)).

You can writee^((ln(3)*ln(2))as:

3^(ln(2))

or

2^(ln(3))

So, the final result is:2.1414860639032773

Dms

yes if u plug it into a calculator thats what you will obtain however math_lover101 is asking for the exact exponent as previously stated

Guest Mar 14, 2014

#4**0 **

Yes, but its:

juicybebe101:yes if u plug it into a calculator thats what you will obtain however math_lover101 is asking for the exact exponent as previously stated

Yes, but its:

e^(ln(6))

So, the only solutions are:*3^(ln(2))* __AND__ *2^(ln(3))*

Dms

So, the only solutions are:

Dms

Dms Mar 14, 2014

#5**0 **

How do you find the exponent for this problem "e^((ln(3)*ln(2))"?

I think that there might be some confusion over this problem.

Let's look at a "log" rule:

We have

log(a*b) = log a + log b

But we DON'T have any specific "rule" for log(a) * log (b). In essence, we just "plug" ln(2)*ln(3) straight into a calculator to find the exponent!!

Note...if we had e^(lh(2) + ln(3)), this would mean the same thing as e^(ln(2))*e^(ln(3)) and THAT answer**Is** = "6"......This is based on the rule that e^(ln(a)) = a

I hope this helps.

I think that there might be some confusion over this problem.

Let's look at a "log" rule:

We have

log(a*b) = log a + log b

But we DON'T have any specific "rule" for log(a) * log (b). In essence, we just "plug" ln(2)*ln(3) straight into a calculator to find the exponent!!

Note...if we had e^(lh(2) + ln(3)), this would mean the same thing as e^(ln(2))*e^(ln(3)) and THAT answer

I hope this helps.

CPhill Mar 14, 2014

#6**0 **

I will say the same as the CPhill and Dms, (oh, juicybebe, do you agree now?)

math_lover101:How do you find the exponent for this problem "e^((ln(3)*ln(2))"?

I will say the same as the CPhill and Dms, (oh, juicybebe, do you agree now?)

e^((ln(3)*ln(2))

OR

e^{ln(3)*ln(2)} ==> {e ^{ln(3)}}^[ln(2)] ==> 3 ^{ln2} ==> 2.14148.....

OR

e^{ln(2)*ln(3)} ==> {e ^{ln(2)}}^[ln(3)] ==> 2 ^{ln3} ==> 2.14148.....

Now I think that this is an irrational number which means that no matter how many digits you express it to it will still be an approximation

OR

e

OR

e

Now I think that this is an irrational number which means that no matter how many digits you express it to it will still be an approximation

Melody Mar 15, 2014