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how do you find the exact value of each expression of sec 7pi/6

 Jan 27, 2016

Best Answer 

 #1
avatar+130466 
+10

sec (7pi/6)   =  1 / cos(7pi/6)  = 1/cos(210°)  = 1/ [-sqrt(3)/2]  = -2/sqrt(3)

 

Remember that 210°  is a 30°  reference angle in the 3rd quadrant and cos(30°)  = sqrt(3)/2.....but the cos is negative in the 3rd quadrant........

 

 

cool cool cool

 Jan 27, 2016
 #1
avatar+130466 
+10
Best Answer

sec (7pi/6)   =  1 / cos(7pi/6)  = 1/cos(210°)  = 1/ [-sqrt(3)/2]  = -2/sqrt(3)

 

Remember that 210°  is a 30°  reference angle in the 3rd quadrant and cos(30°)  = sqrt(3)/2.....but the cos is negative in the 3rd quadrant........

 

 

cool cool cool

CPhill Jan 27, 2016

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