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Exits on a highway are numbered consecutively from 1 to 50. The distance from exit 41 to exit 50 is 100 km. If each exit is at least 6 km from the next exit, what is the longest possible distance, in kilometers, between exit 47 and exit 48?

 Apr 3, 2020
 #1
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6km each minumum for 41-50   covers 9 exits     9 x 6 = 54 km to meet minumum   leaving 100-54= 46 km that can be added to the 6km

between 47 and 48    46 + 6 = 52 km

 Apr 3, 2020
 #2
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There are 9 "sections" from exit 41 to exit 50.

If 8 of these exits are 6 km each, this would account for 8 x 6  =  48 km.

Since the total distance from exit 41 to exit 50 is 100 km, the maximum distance from exit 47 to exit 48

is  100 km - 48 km  =  52 km.

 Apr 3, 2020

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