Exits on a highway are numbered consecutively from 1 to 50. The distance from exit 41 to exit 50 is 100 km. If each exit is at least 6 km from the next exit, what is the longest possible distance, in kilometers, between exit 47 and exit 48?
6km each minumum for 41-50 covers 9 exits 9 x 6 = 54 km to meet minumum leaving 100-54= 46 km that can be added to the 6km
between 47 and 48 46 + 6 = 52 km
There are 9 "sections" from exit 41 to exit 50.
If 8 of these exits are 6 km each, this would account for 8 x 6 = 48 km.
Since the total distance from exit 41 to exit 50 is 100 km, the maximum distance from exit 47 to exit 48
is 100 km - 48 km = 52 km.
