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Expand Log6(3√3/36y4) then condense.

The Logarithmic base is 6.

Are any of the solutions from this topic correct? Or is it something else entirely?
http://www.mymathforum.com/viewtopic.php?f=13&t=42035

I'd like the answer please.
 Aug 7, 2013
 #1
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Now I'm being told this is correct. Which is it?!

"Log6(3√3) - Log6(36y^4)
Log6(3√3) - 4Log6(36y)
Log6(3) + Log6(√3) - [4Log6(36) + 4Log6(y) ]
Log6(3) + Log6(3^(1/2)) - [4Log6(36) + 4Log6(y)]
Log6(3) + 1/2 Log6(3) - [4Log6(36) + 4Log6(y)]

Condensing is doing the same thing in reverse, remember that Sqrt sign means the exponent is to the 1/2 power!"
 Aug 7, 2013
 #2
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Use more braces. Log6(3√3/36y4) could be anything:
log6(3*(sqrt(3)/36)*y4)
log6(3*(sqrt(3)/36y)*4)
log6(3*sqrt(3)/36y^4)
log6(3*sqrt(3/36)*y4)
log6(3*sqrt(3/36y)*4)
log6(3*sqrt(3/36y^4))

So which is it?
 Aug 7, 2013

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