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avatar+1836 

Expand $(\sqrt{z} + 2z)^4+(\sqrt{z} - 2z)^4$

 May 7, 2015

Best Answer 

 #2
avatar+118673 
+18

$$\\(\sqrt{z})^4+4(\sqrt{z})^3(2z)+6(\sqrt{z})^2(2z)^2+4\sqrt{z}(2z)^3+(2z)^4+\\
(\sqrt{z})^4-4(\sqrt{z})^3(2z)+6(\sqrt{z})^2(2z)^2-4\sqrt{z}(2z)^3+(2z)^4\\\\
=2*(\sqrt{z})^4+2*6(\sqrt{z})^2(2z)^2+2*(2z)^4\\
=2*z^2+2*6z*4z^2+2*16z^4\\
=2z^2+48z^3+32z^4\\$$

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 May 7, 2015
 #1
avatar+5 
-1

TOO HARD. 

 May 7, 2015
 #2
avatar+118673 
+18
Best Answer

$$\\(\sqrt{z})^4+4(\sqrt{z})^3(2z)+6(\sqrt{z})^2(2z)^2+4\sqrt{z}(2z)^3+(2z)^4+\\
(\sqrt{z})^4-4(\sqrt{z})^3(2z)+6(\sqrt{z})^2(2z)^2-4\sqrt{z}(2z)^3+(2z)^4\\\\
=2*(\sqrt{z})^4+2*6(\sqrt{z})^2(2z)^2+2*(2z)^4\\
=2*z^2+2*6z*4z^2+2*16z^4\\
=2z^2+48z^3+32z^4\\$$

Melody May 7, 2015

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