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Expand $(\sqrt{t} + 2t)^4+(\sqrt{t} - 2t)^4$.

 Jun 8, 2022
 #1
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\(t^2+8t\left(\sqrt{t}\right)^3+24t^3+32t^3\sqrt{t}+16t^4+\left(\sqrt{t}-2t\right)^4\)

 

\(t^2+8t\left(\sqrt{t}\right)^3+24t^3+32t^3\sqrt{t}+16t^4+t^2-8t\left(\sqrt{t}\right)^3+24t^3-32t^3\sqrt{t}+16t^4 \)

 

\(32t^4+48t^3+2t^2\)

 

-Vinculum

 

smileysmileysmiley

 Jun 8, 2022

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