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Question

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Find 25^{1/2-log5(root2)}

and then another problem that has stumped me:

Find (Log₂₅8)(log_1/25)

Tacoflea Apr 18, 2023

Guest · Answer 1 · 2023-04-18T05:59:04

Use properties of logs: \(25^{1/2 - \log_5 \sqrt{2}} = \dfrac{2}{5}\)