I need help with these
Suppose we have a bag with 10 slips of paper in it. Eight slips have a 3 on them and the other two have a 5 on them.
(a) What is the expected value of the number shown when we draw a single slip of paper?
(b) What is the expected value of the number shown if we add one additional 3 to the bag?
(c) What is the expected value of the number shown if we add two additional 3's (instead of just one) to the bag?
(a) The expected value of the number shown when we draw a single slip of paper is:
E(X) = (8/10) * 3 + (2/10) * 5 = 2.8
(b) If we add one additional 3 to the bag, there will be a total of 9 slips with a 3 on them and 2 slips with a 5 on them. The expected value of the number shown is:
E(X) = (9/11) * 3 + (2/11) * 5 = 2.81
(c) If we add two additional 3's to the bag, there will be a total of 10 slips with a 3 on them and 2 slips with a 5 on them. The expected value of the number shown is:
E(X) = (10/12) * 3 + (2/12) * 5 = 2.83
Note that the expected value increases as we add more slips with a 3 on them to the bag. This makes sense, since the mode of the distribution is 3, and adding more slips with a value of 3 makes it more likely that we will draw a 3.