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# Explain...?

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Write down an algebraic equation that represents this problem.

Feb 27, 2018

#1
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Let's call the number that one is thinking of "x."

If I take "x" and I multiply "x" by 3, then I have "3x."

If I take "3x" and I add "4," then I have "3x+4."

If I have "3x+4" and I divide by 4, then I have $$\frac{3x+4}{4}$$.

If the original number is "x," then three less than "x" is x-3.

We know that $$\frac{3x+4}{4}$$ and $$x-3$$ are equivalent because of the keyword "is."

Therefore, the final algabraic equation would be $$\frac{3x+4}{4}=x-3$$

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Feb 27, 2018
#2
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Thanks! I don't know if you can, but can you solve it?

Guest Feb 27, 2018
#3
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Sure, you can:

Solve for x:

(3 x + 4)/4 = x - 3  cross multiply

3x + 4 = 4x - 12    move x to the LHS

3x - 4x = - 12 - 4

- x = - 16              Multiply both sides by -1

x = 16

Feb 27, 2018