#1**0 **

Let's call the number that one is thinking of "x."

If I take "x" and I multiply "x" by 3, then I have "3x."

If I take "3x" and I add "4," then I have "3x+4."

If I have "3x+4" and I divide by 4, then I have \(\frac{3x+4}{4}\).

If the original number is "x," then three less than "x" is x-3.

We know that \(\frac{3x+4}{4}\) and \(x-3\) are equivalent because of the keyword "is."

Therefore, the final algabraic equation would be \(\frac{3x+4}{4}=x-3\)

TheXSquaredFactor
Feb 27, 2018