Step by step, how would one solve cos^-1(-sqrt(2)/2) in degrees not radians?
cos-1( -√(2)/2 )
Since the cos has a negative value, it will be found in either the second quadrant or the third quadrant.
The cos will have a value of -√(2)/2 at either 135° or 225° (plus multiples of 360°).
The value of cos which is √(2)/2 occurs at 45°;
in the second quadrant, this occurs at 45° above 180° (or 135°);
in the third quadrant, this occurs at 45° below 180° (or 225°).
cos-1( -√(2)/2 )
Since the cos has a negative value, it will be found in either the second quadrant or the third quadrant.
The cos will have a value of -√(2)/2 at either 135° or 225° (plus multiples of 360°).
The value of cos which is √(2)/2 occurs at 45°;
in the second quadrant, this occurs at 45° above 180° (or 135°);
in the third quadrant, this occurs at 45° below 180° (or 225°).