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Step by step, how would one solve cos^-1(-sqrt(2)/2) in degrees not radians?

 May 28, 2015

Best Answer 

 #1
avatar+23247 
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cos-1( -√(2)/2 )

Since the cos has a negative value, it will be found in either the second quadrant or the third quadrant.

The cos will have a value of -√(2)/2  at either 135° or 225°  (plus multiples of 360°).

The value of cos which is √(2)/2 occurs at 45°;

  in the second quadrant, this occurs at 45° above 180° (or 135°);

  in the third quadrant, this occurs at 45° below 180° (or 225°).

 May 28, 2015
 #1
avatar+23247 
+10
Best Answer

cos-1( -√(2)/2 )

Since the cos has a negative value, it will be found in either the second quadrant or the third quadrant.

The cos will have a value of -√(2)/2  at either 135° or 225°  (plus multiples of 360°).

The value of cos which is √(2)/2 occurs at 45°;

  in the second quadrant, this occurs at 45° above 180° (or 135°);

  in the third quadrant, this occurs at 45° below 180° (or 225°).

geno3141 May 28, 2015

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