If \(x\) is a real number such that \(2^{2x+3}=14\) , find \(2^x\). Thank you!
Solve for x over the real numbers: 2^(2 x + 3) = 14
Take the logarithm base 2 of both sides: 2 x + 3 = log(14)/log(2)
Subtract 3 from both sides: 2 x = log(14)/log(2) - 3
Divide both sides by 2: x = log(14)/(2 log(2)) - 3/2 ≈0.403677
+12 
